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TPS5430DDA

Part # TPS5430DDA
Description 5.5V -36V INPUT, 3-A STEP DOWN CONVERTER - Rail/Tube
Category IC
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Technical Document


DISCLAIMER: The information provided herein is solely for informational purposes. Customers must be aware of the suitability of this product for their application, and consider that variable factors such as Manufacturer, Product Category, Date Codes, Pictures and Descriptions may differ from available inventory.

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Internal Compensation Network
H(s)
1
s
2Fz1
1
s
2Fz2
s
2Fp0
1
s
2Fp1
1
s
2Fp2
1
s
2Fp3
(15)
Thermal Calculations
TPS5430
SLVS632 JANUARY 2006
This equation assumes nominal on resistance for the high side FET and accounts for worst case variation of
operating frequency set point. Any design operating near the operational limits of the device should be
carefully checked to assure proper functionality.
The design equations given in the example circuit can be used to generate circuits using the TPS5430. These
designs are based on certain assumptions and will tend to always select output capacitors within a limited range
of ESR values. If a different capacitor type is desired, it may be posssible to to fit one to the internal
compensation of the TPS5430. Equation 15 gives the nominal frequency response of the internal voltage-mode
type III compensation network:
Where
Fp0 = 2165 Hz, Fz1 = 2170 Hz, Fz2 = 2590 Hz
Fp1 = 24 kHz, Fp2 = 54 kHz, Fp3 = 440 kHz
Fp3 represents the non-ideal parasitics effect.
Using this information along with the desired output voltage, feed forward gain and output filter characteristics,the
closed loop transfer function can be derived.
The following formulas show how to estimate the device power dissipation under continuous conduction mode
operations. They should not be used if the device is working at light loads in the discontinuous conduction mode.
Conduction Loss: Pcon=Io
2
× Rds,on × VOUT/VIN
Switching Loss: Psw = VIN × IOUT × 0.01
Quiescent Current Loss: Pq = VIN × 0.01
Total Loss: Ptot = Pcon + Psw + Pq
Given T
A
=> Estimated Junction Temperature: T
J
= T
A
+ Rth × Ptot
Given T
JMAX
= 125 ° C => Estimated Maximum Ambient Temperature: T
AMAX
= T
JMAX
Rth x Ptot
16
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PERFORMANCE GRAPHS
-0.3
-0.2
-0.1
0
0.1
0.2
0.3
0 0.5 1 1.5
2
2.5 3
I - Output Current - A
O
Output Regulation - %
75
80
85
90
95
100
0 0.5 1 1.5 2 2.5 3 3.5
I - Output Current - A
O
Efficiency - %
V = 15 V
I
V = 10.8 V
I
V = 12 V
I
V = 18 V
I
V = 19.8 V
I
t -Time - 500 ns/Div
PH = 5 V/Div
V = 100 mV/Div (AC Coupled)
IN
-0.1
-0.08
-0.06
-0.04
-0.02
0
0.02
0.04
0.06
0.08
0.1
10.8 13.8 16.8 19.8
V - Input Voltage - V
I
Input Regulation - %
I = 0 A
O
I = 3 A
O
I = 1.5 A
O
TPS5430
SLVS632 JANUARY 2006
The performance graphs in Figures 12 - 18 are applicable to the circuit in Figure 10. Ta = 25 ° C. unless
otherwise specified.
Figure 13. Efficiency vs. Output Current Figure 14. Output Regulation % vs. Output Current
Figure 15. Input Regulation % vs. Input Voltage Figure 16. Input Voltage Ripple and PH Node, Io = 3 A.
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t - Time = 200 ms/Div
I = 1 A /Div
OUT
V = 50 mV/Div (AC Coupled)
OUT
t - Time = 500 ns/Div
PH = 5 V/Div
V = 20 mV/Div (AC Coupled)
OUT
t - Time = 2 ms/Div
V = 2 V/Div
OUT
V = 5 V/Div
IN
TPS5430
SLVS632 JANUARY 2006
Figure 17. Output Voltage Ripple and PH Node, Io = 3 A Figure 18. Transient Response, Io Step 0.75 to 2.25 A.
Figure 19. Startup Waveform, Vin and Vout.
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